Two separate loads wired in parallel to the source will be given equal amounts of voltage to each load. Also, the total current will equal the sum of the current ran through each load wired in parallel. And since you are using like impedances for each load, the individual current through each of the 2 loads will equal each other, therefore total current will be divided evenly by the number of loads that are wired in parallel to the source. And that can be calculated to show that each load is being given half of the power (wattage) of the total output in your instance. So essentially the answer is, Yes.
You really weren't thinking you'd get an answer without a full explaination?