Thread: Has anyone tried Prosport Gauge senders?

I have some more info...

Oil pressure sender uses 0-5V, so I expect that to work ok on the FB with nothing else added.

Oil temperature uses 32-925 oHms (on a 12V DC car system). I expect to have to use a resistor. Is that correct and which one?

Is there a tutorial on how to wire up the resistor?

Yes. There's a similar thread here for air pressure senders:

http://www.mp3car.com/vbulletin/fb-d...uspension.html

you'll want a resistor somewhere around 400 ohms. You'll need to generate the curvefit yourself.

And feed it from a voltage regulated circuit - eg, the FB.

PS - Don't they provide linearity data?
And 10 bar seems overkill for fuel pressure; even oil pressure!

Originally Posted by OldSpark

And feed it from a voltage regulated circuit - eg, the FB.

PS - Don't they provide linearity data?
And 10 bar seems overkill for fuel pressure; even oil pressure!

I see 6bar continuous and 8bar spikes on my SR20DET.

Originally Posted by greenman100

I see 6bar continuous and 8bar spikes on my SR20DET.

Hopefully not for oil pressure LOL!

How long do the spikes last?
And I presume that isn't a 3-Bar system with 3-Bar continuous & up to 5-Bar boost?

So I have ordered my Fusion Brain and I have the Prosport senders. Now I'm feeling intimidated by putting this together. Expecting to do something stupid and fry the FB.

Any help will be most welcome.

The pressure sensor is three wire; 12V, Signal, Grnd.
Signal range is 0-5V

The temp sensor is two wire and came with no instructions. I'm assuming 12V and Grnd and the FB must measure the resistance between the two. Sensor should put out between 32 and 925 ohms.

How should these be wired up and what tests should I do before pluging these into the FB?

wikipedia Voltage_divider

Forget the Wiki padding - go straight to Resistive divider with the R1 & R2 diagram and that Vo = Vi x R2/(R1+R2).

Also be aware that the voltage across a resistance is equal to the size of the resistor (Ohms) times the current thru it (Amps). In other works (or symbols...)...
V = IR (V=Volts, I&R = Amps and Ohms else mA & kOhms.)

So to convert resistance to voltage, add a resistor in series and place both across a voltage. (Though you might want a constant current source for the temp sensor if powering it from 5V and wanting a reasonable voltage swing: If R = 50 Ohms @ 5V, that's I = V/R = 5/50 = 0.1A. Power (Watts) =VI = 5 x 0.1 = 1/2W which might be getting a bit high... FYI: P=VI = VV/R = IIR by substituting V=IR into P=VI)

And you might need to use the voltage divider to reduce sensor outputs to a suitable range (eg 0-5V to 0-4V etc).

My assumption about the temp sensor was wrong. It uses signal and ground (not power and ground) so must be expecting power through the signal wire.

Yep - hence my resistive rant. (7 of 9 was was correct - Resistance is NOT futile.)

The temp sensor is a resistor - albeit temperature dependent - aka a thermistor.
Hence is is a simple passive two terminal device - usually packaged with case ground and single terminal, else electrically isolated 2-terminals.

You would have it as R2 in my previous post.