Thread: anyone know how to solve this? (my elect's class) quick ?

1. anyone know how to solve this? (my elect's class) quick ?

I am having a hard time with this one: (not meant to be a long thread, just need solution)

2. 1.5 kohms, taken across the load terminals. Thevenin voltage is (Va / 8) if you need that too. If you want to know how, just ask

3. i know you remove the load and calculate resistance but thats where I get lost, if you can just tell me how you got 1.5k then I will be set.

(sorry I have no instructor to ask physical ?'s, online class)

4. To calculate the the total resistance also replace all the voltage source by short circuit and current source with open circuits.

So if u start from left most side
R1 in parallel with R2 = R1-2 = 1K
R1-2 in series with R3 = R1-3 = 2K
R1-3 in parallel with R4 = R1-4 = 1K
R1-4 in series with R5 = R1-5 = 2K
R1-5 in Parallel with R6 = R1-6 = 1K
R1-6 in series with R7 = Rth = 1.5K

5. thanks, makes sence now

6. hehe, one more ?

sorry, I wont clutter the boards up anymore after this

could one of you guys just show steps, I have looked at examples in books and site and what not but they deal with voltage dividers, so one example will help me VERY much

APPRECIATE IT!

7. I get 0.035mA for I Load. (not one of the answers given). got a thevenin equivalent circuit (Vth = 0.475V, Rth = 3.6kOhms) and used that to calc the load current. Must have stuffed up one of the thevenins.

8. wow

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