shouldnt pin 86 be grounded on the relay, in the 90 sec power off delay circuit, or is there a special reason its connected to the positive wire of the inverter.
If my relay stays charged for 1m 15 sec with 5,700uF at 12v, then 10x10,000uf (1,000,000uf) should stay charged for (1000000\5700=175.4*75sec=13155sec) 219m 15sec. I'm a newb at electronics, too, so don't feel out of place! If my thinking is correct, and the calculations are linear, the caps you are using should keep that relay charged for at least 3.6 HOURS!
Of course, the Ohms rating of the relay will significantly affect this time. I used a standard BOSCH relay, so unless yours is substantially less efficient (higher ohms) than mine, my numbers work.
This equals 100,000uf, which ends up being about 21.9 minutes, not 219. My time was less then your times, I am sure it is because of the relay, it is a bosch type. I found that if I added some resistance to the negative end of the caps I could extend the 7.5 minutes I get now by about 2 minutes, but I don't need to.Originally Posted by PatO
Using a transistor + small caps is a better idea than 10x10000, smaller and cheaper, but . . . .
Please check again your drawing at Ghetto Startup/Shutdown Control for Inverter
If your delayed relay followed that diagram now work, I am affraid you've done a wrong wiring.
Really it shouldn't work with that drawing.
Ooops... Thanks for pointing that out! (damn MS Calculator not placing commas'!)
Ya - 21.9m ~ 7.5 could be attributed to the relay.
Which diagram are you referring to? There's so many in here now... can you provide a link? Mine wasnt connected to the +ve of the inverter...Originally Posted by remarque
It does work, I built it, how could it be wrong?Originally Posted by lexanite
Originally Posted by Heywood
I just remind PatO that the drawing in Ghetto Startup/Shutdown Control for Inverter was wrong.Originally Posted by Heywood
1. The diode at the relay coil reverse connected.
There will be no current flow at the relay coil because of the diode, means the current will flow through the diode instead of the coil.
3. Current path missing: please explain at that drawing, how the current will flow from +ve battery through the relay coil.
Please check again few pages backward, or http://www.mp3car.com/vbulletin/show...691#post662691
Anyway the drawing is not important as long as the hardware can work. In the worst case, some people don't even need any drawing to make this kind of thing.
Wouldnt it be easier use super caps, instead of using a lot of 10000uf caps? I order 4 off ebay for $7.00 and they .22F, they have some that are 1F and they are about the size of penny. Plus you dont have to make a complicated circuit, it can be hooked directly to the relay and once the power is cut it will keep the relay charged.