Thread: Laptop-battery (14.4V) to power Lilliput (12V)

Originally Posted by Danneman

Is it possible to somehow diminish the voltage-output of a laptop-battery (which outputs 14.4V) to 12 Volt, so it can be used to power devices running on 12 V (like the Lilliput, for instance)?

And if so, how? Using resistors?

Its possible , use the linear regulator LM7812 (1A out) and dissipate the regulator.
Or 3 diodes in series type 1N4007 , on the positive thread with Anode of the first diode in Input and Katod of the last one toward the feeding of the lilliput.
Every diode decreases of 0,7v around the tension.
You should get so around the 12,3/12,4V, for the Lilliput I am ok up to 12,6V.

Thanks a lot mauri

Btw, is there a functional difference between diodes and resistors (other than that diodes makes sure current run i a specific direction)? Just curious

Originally Posted by Danneman

Thanks a lot mauri

Btw, is there a functional difference between diodes and resistors (other than that diodes makes sure current run i a specific direction)? Just curious

A huge difference.
The diode and' a semiconductor, that is' it allows to pass only the tension from 1 side and from the other one no.
The resistance allows to pass from everybody and two the sides, only that in base to its value ohmnic "cuts" of a little.
This in poor words, make to understand you, even if the explanation should be very more' complex!

PS: remembered that with the diodes that I have pointed out you you don't have to overcome a tide of 1A that it crosses them.
To use as feeder for the Lilliput you/they should be ok, it consumes less than 1A.
I recommend you to use a regulator LM7812 however, and' more' sure, rules surely Always in every condition on the 12V, also because' in automotive they are many the starts of tension, and with the diodes you would not get the same results.
And then and' simple to do

Mauri

Thanks again - you live and you learn

Yeah, I think Ill go with the regulator, since I dont want to take any chances with the screen.