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Old 08-11-2006, 09:53 PM   #3
Maheriano
FLAC
 
Join Date: May 2006
Location: Calgary, Alberta
Posts: 936
The first link doesn't really help, I've been working with this one of the past hour or so. http://www.bcae1.com/wire.htm

So using the calculations on that page, I have:

Resistance:
R = 1 / 1.26 ^ (difference between 8awg and 10awg)
R = 1 / 1.26 ^ 2
R = 1 / 1.586
R = .629881582

Amps:
I = E / R
I = 12 / .629881582
I = 19.051200008

Is this right? Hey, I'm using the resources you're giving me and trying. If someone explained the rest, it wouldn't be spoon feeding. My next question is, "Do I now get the amp rating for my speaker amp, add it to the 19 for my sub amp and use that to see if it'd draw too much power on the single 8 gauge going from the distribution block to the battery?"
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